已知a²-√7a+1=0(1)a+1/a的值为------(2)求a²+1/a²的值
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已知a²-√7a+1=0(1)a+1/a的值为------(2)求a²+1/a²的值
已知a²-√7a+1=0
(1)a+1/a的值为------
(2)求a²+1/a²的值
已知a²-√7a+1=0(1)a+1/a的值为------(2)求a²+1/a²的值
已知a²-√7a+1=0
(1)a+1/a的值为------
a-√7+1/a=0;
a+1/a=√7;
(2)求a²+1/a²的值
=(a+1/a)²-2
=7-2
=5;
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答:
a²-√7a+1=0
显然a不为0,两边同除以a得:
a-√7+1/a=0
a+1/a=√7
所以:a>0
两边平方得:
(a+1/a)²=7
a²+2+1/a²=7
a²+1/a²=5
综上所述:a+1/a=√7,a²+1/a²=5