2√3×^6√12׳√3/2(那个6是在根号的左上角)求详细的解题过程,
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/15 03:43:46
![2√3×^6√12׳√3/2(那个6是在根号的左上角)求详细的解题过程,](/uploads/image/z/8852797-37-7.jpg?t=2%E2%88%9A3%C3%97%5E6%E2%88%9A12%C3%97%26%23179%3B%E2%88%9A3%EF%BC%8F2%EF%BC%88%E9%82%A3%E4%B8%AA6%E6%98%AF%E5%9C%A8%E6%A0%B9%E5%8F%B7%E7%9A%84%E5%B7%A6%E4%B8%8A%E8%A7%92%EF%BC%89%E6%B1%82%E8%AF%A6%E7%BB%86%E7%9A%84%E8%A7%A3%E9%A2%98%E8%BF%87%E7%A8%8B%2C)
xŒJ@_% Ȅę1ɋH}.CR\B[p7ͥ'4HNɨm>
\`$pqSKRأEiEE؝p6^ϯ}_Ev2dػSo7Pںw@T!rn,4<aMd:f%;"6TX¿i"[%-)hcijUEɶFX^EL*ypaC#ky'Ww7!i.Jdp1)xNK% bEpx
s*gmCEBi
2√3×^6√12׳√3/2(那个6是在根号的左上角)求详细的解题过程,
2√3×^6√12׳√3/2(那个6是在根号的左上角)求详细的解题过程,
2√3×^6√12׳√3/2(那个6是在根号的左上角)求详细的解题过程,
2√3×^6√12׳√(3/2)
=2×[3^(1/2)]×[12^(1/6)]×[(3/2)^(1/3)]
=2×[3^(1/2)]×[(3×2×2)^(1/6)]×[(3×1/2)^(1/3)]
=2×[[3^(1/2)]×[3^(1/6)]×[2^(1/6)]×[2^(1/6)]×[3^(1/3)]×[2^(-1/3)]
=2×[3^(1/2+1/6+1/3)]×[2^(1/6+1/6-1/3)]
=2×(3^1)×(2^0)
=2×3×1
=6
【利用幂的性质:
①x^m/n = n√x^m
②a^nxa^m=a^(n+m)
③(axb)^n=a^n×b^n
④n^m=1/n^(-m),(m