计算:8^(1-log(83))(27^(2/3))-log(32)
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/28 00:26:06
x){nueaaaadad4mq(Kaѡ_`gC5:0m-oꄊ$فl 2AR
计算:8^(1-log(83))(27^(2/3))-log(32)
计算:8^(1-log(83))
(27^(2/3))-log(32)
计算:8^(1-log(83))(27^(2/3))-log(32)
8^(1-log(8,3))
=8^1÷8^log(83)
=8/3
计算:8^(1-log(83))(27^(2/3))-log(32)
计算:(1) log(2)(3)*log(3)(4)*log(4)(5)(2)log(2)(7)*log(√7)(8)
对数计算1.{log(4)(3)+ log(8) (3)} X {log(3)(2)+log(9)(2)}2.{log(2)(3)} X {log(3)(4)+log(9)(2)}3.(lg2)^+1g2X 1g5 +1g50
1、log下标3 2(log下标4 3+log下标8 3)2、log下标1/3 √27+log下标27 1/3
计算:2log(2)3-log(2)9/8
计算:1/[log(2)3]+1/[log(5)3]=?
计算:log以4为底8的对数减log以9为底1/27的对数+log以根号2为底4的对数=?
1.求值25^log(5)^3+lg100+log(1/2)4.2.9^log(3)^5的值为( ).A.5 B.15 C.25 D.453.计算log(2)2+log(5)1-log(1/3)1/27+[3^log(3)5]^2+3^log(3)2.
(iog(4)3+log(8)3)(log(3)2+log(9)8)怎样计算
(log(2)9+log(4)1/9)乘以(log(3)2+log(9)0.5) 括号里是底数.计算这道题.
log(1/8)X
计算:(1).(27/8)^(1/3)+lg根号2+lg根号5+2^log(2)3+ln1 (2).(1/2)^-1+log(0.5)8
计算:log小2 根号7/48+log小2 12-1/2log小2 42
如何计算LOG
log平方的计算
计算log(2)3/8的绝对值+log(2)3/2的绝对值=?
计算2001°+log(2)25*log(5)8=?这题的答案应该是:16....
如何计算啊.(log底数4真数3+log底数8真数3)乘(log底数3真数2+log底数9真数2)=?