若实数x,y满足x²+y²-12x+4y+40=0,求xsin(-25兀/3)+ysin(-15兀/4)的值.
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若实数x,y满足x²+y²-12x+4y+40=0,求xsin(-25兀/3)+ysin(-15兀/4)的值.
若实数x,y满足x²+y²-12x+4y+40=0,求xsin(-25兀/3)+ysin(-15兀/4)的值.
若实数x,y满足x²+y²-12x+4y+40=0,求xsin(-25兀/3)+ysin(-15兀/4)的值.
x=6,y=-2,原式=6sin(-pai/3)-2sin(pai/4)=-3跟号3-跟号2