关于高数2的简单的导数问题!例题是这样的!求y=cosln(1+2x)的导数做法为设y=cosu,u=ln(1+2x)=lnv,v=1+2xdy/dx=(dy/du)*(du/dv)*(dv/dx)=-sinu*(1/v)*2.但我怎么也看不懂这是怎么做的,不是复合函数求导公式是dy/dx=
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![关于高数2的简单的导数问题!例题是这样的!求y=cosln(1+2x)的导数做法为设y=cosu,u=ln(1+2x)=lnv,v=1+2xdy/dx=(dy/du)*(du/dv)*(dv/dx)=-sinu*(1/v)*2.但我怎么也看不懂这是怎么做的,不是复合函数求导公式是dy/dx=](/uploads/image/z/8897675-59-5.jpg?t=%E5%85%B3%E4%BA%8E%E9%AB%98%E6%95%B02%E7%9A%84%E7%AE%80%E5%8D%95%E7%9A%84%E5%AF%BC%E6%95%B0%E9%97%AE%E9%A2%98%21%E4%BE%8B%E9%A2%98%E6%98%AF%E8%BF%99%E6%A0%B7%E7%9A%84%21%E6%B1%82y%3Dcosln%281%EF%BC%8B2x%29%E7%9A%84%E5%AF%BC%E6%95%B0%E5%81%9A%E6%B3%95%E4%B8%BA%E8%AE%BEy%3Dcosu%2Cu%3Dln%281%2B2x%29%3Dlnv%2Cv%3D1%2B2xdy%2Fdx%3D%28dy%2Fdu%29%2A%28du%2Fdv%29%2A%28dv%2Fdx%29%3D-sinu%2A%281%2Fv%29%2A2.%E4%BD%86%E6%88%91%E6%80%8E%E4%B9%88%E4%B9%9F%E7%9C%8B%E4%B8%8D%E6%87%82%E8%BF%99%E6%98%AF%E6%80%8E%E4%B9%88%E5%81%9A%E7%9A%84%2C%E4%B8%8D%E6%98%AF%E5%A4%8D%E5%90%88%E5%87%BD%E6%95%B0%E6%B1%82%E5%AF%BC%E5%85%AC%E5%BC%8F%E6%98%AFdy%2Fdx%3D)
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