若Y/X=3/2,Y/Z=3/4.则2XY+YZ/2YZ-XY=多少
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若Y/X=3/2,Y/Z=3/4.则2XY+YZ/2YZ-XY=多少
若Y/X=3/2,Y/Z=3/4.则2XY+YZ/2YZ-XY=多少
若Y/X=3/2,Y/Z=3/4.则2XY+YZ/2YZ-XY=多少
对于分式 (2XY+YZ)/(2YZ-XY)
因为Y/X=3/2,Y/Z=3/4 所以X/Z=1/2
所以
分子和分母同时除以YZ可以得到:
原分式=(2X/Z + 1)/(2-X/Z)
=(2*1/2 + 1) / (2-1/2)
=4/3
Y/X=3/2
X=2Y/3
Y/Z=3/4
Z=4Y/3
2XY+YZ/2YZ-XY
=(2*2Y/3*Y+Y*4Y/3)/(2*Y*4Y/3-2Y/3*Y)
=[(8/3)Y²]/(2Y²)
=4/3
首先看此式每一项中都包含Y,那么用Y分别表示X和Z,X=2/3Y,Z=4/3Y,
则(2XY+YZ)/(2YZ-XY)
=(4/3Y²+4/3Y²)/(8/3Y²-2/3Y²)
=(4/3+4/3)/(8/3-2/3)
=4/3
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