log(a)2
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log(a)2
log(a)2
log(a)2
因为真数2>1,对数值都小于0,所以两底数均在0到1之间
loga 2<logb 2
此时底数越大对数值越小
a>b
0<b<a<1
log(a)2
log a 2/3
log a(2/3)
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27-1/ 若a>0,b>0,a*b>1,log(1/2)[a]=ln2,则log(a)[b]与log(1/2)[a]的关系是:()?(A)log(a)b< log(1/2)[a](B)log(a)b= log(1/2)[a](C)log(a)b>log(1/2)[a](D)log(a)b与log(1/2)[a] 无法比较大小我做到一半就做不下去了:a=(1/2)^(ln2)log