作业帮x/(x-2)+(x+9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)怎样解这道方程
来源：学生作业帮助网 编辑：作业帮 时间：2024/06/03 01:38:02
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x/(x-2)+(x+9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)怎样解这道方程
x/(x-2)+(x+9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)怎样解这道方程
x/(x-2)+(x+9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)怎样解这道方程
x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)
1+2/(x-2)+1-2/(x-7)=1+2/(x-1)+1-2/(x-6)
1/(x-2)-1/(x-7)=1/(x-1)-1/(x-6)
-5/(x-2)(x-7)=-5/(x-1)(x-6)
(x-2)(x-7)=(x-1)(x-6)
x^2-9x+14=x^2-7x+6
2x=8
x=4
应该是
x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)
1+2/(x-2)+1-2/(x-7)=1+2/(x-1)+1-2/(x-6)
1/(x-2)-1/(x-7)=1/(x-1)-1/(x-6)
-5/(x-2)(x-7)=-5/(x-1)(x-6)
(x-2)(x-7)=(x-1)(x-6)
x^2-9x+14=x^2-7x+6
2x=8
x=4