{(m+n/2)+(m-2/3)=6,4(m+n)-5(m-n)=2 用加减消元法解二元一次方程急求解答谢谢!
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{(m+n/2)+(m-2/3)=6,4(m+n)-5(m-n)=2 用加减消元法解二元一次方程急求解答谢谢!
{(m+n/2)+(m-2/3)=6,4(m+n)-5(m-n)=2 用加减消元法解二元一次方程急求解答谢谢!
{(m+n/2)+(m-2/3)=6,4(m+n)-5(m-n)=2 用加减消元法解二元一次方程急求解答谢谢!
{(m+n/2)+(m-2/3)=6
3(m+n)+2(m-2)=36
3m+3n+2m-4=36
5m+3n=40 (1)
,4(m+n)-5(m-n)=2
,4m+4n-5m+5n=2
-m+9n=2
m=9n-2 (2)
5(9n-2)+3n=40
45n-10+3n=40
48n=50
n=25/24
m=59/8
已知3m=4n,则m/m+n+n/m-n-m^2/m^2-n^2=
(m-2n)(2n+m)-(-3m-4n)(4n-3m)=
计算(m+4n)(m-n)-6(m+2n)(m-3n)
(m+4n)(m-n)-6(m+2n)(m-3n)
(m+4n)(m-n)-6(m+2n)(m-3n),
解方程组:{3分之2(m-n)-4分之m+n=-1,6(m+n)-4(2m-n)=16解方程组:{[2(m-n)/3-(m+n)/4=-1,6(m+n)-4(2m-n)=16不是(m+n)/2-(m-n)/3=1 (m+n)/3-(m-n)/4=-1 你看清楚,是:解方程组:{[2(m-n)/3-(m+n)/4=-1,6(m+n)-4(2m-n)=16
.4(m+n)^2*(m+n)^3-7(m+n)(m+n)^4+5(m+n)^5=
m-{n-2m+[3m-(6m+3n)+5n]}=
[(m-n)^2*(m-n)^3]^2/(m-n)^4
[(m-n)^2*(m-n)^3]^2/(m-n)^4
4m(m-n)^2+4n(n-m)^3
(m-n)2(n-m)3(n-m)4化简
(m-n)^3(n-m)^2(m-n)=_____
若m-n=3,3m+2n=2,求代数式6m(m-n)-4n(n-m)的值
已知m,n都为自然数,且m(m-n)-n(n-m)=12,求m,n的值.∴(m-n)(m+n)=1×12=2×6=3×4这步是怎么回事
(m-n)^2*(m-n)^4=?
(3m-n)(m-2n)=()
先化简,再求值.其中m=-1,n=2;6m^2-5m(-m+2n-1)+4m(-3m-2/5n-3/4)