若sinx+sin^2x=1,则cos^2x+cos^4x=?由 sinx+sin^2x=1得 sinx=1-sin^2x=cos^2xcos^2x+cos^4x=cos^2x(1+cos^2x)=sinx(1+sinx)=sinx+sin^2x=1cos^2x(1+cos^2x)=sinx(1+sinx)怎么来的?
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/18 11:16:03
![若sinx+sin^2x=1,则cos^2x+cos^4x=?由 sinx+sin^2x=1得 sinx=1-sin^2x=cos^2xcos^2x+cos^4x=cos^2x(1+cos^2x)=sinx(1+sinx)=sinx+sin^2x=1cos^2x(1+cos^2x)=sinx(1+sinx)怎么来的?](/uploads/image/z/8975074-58-4.jpg?t=%E8%8B%A5sinx%2Bsin%5E2x%3D1%2C%E5%88%99cos%5E2x%2Bcos%5E4x%3D%3F%E7%94%B1+sinx%2Bsin%5E2x%3D1%E5%BE%97+sinx%3D1-sin%5E2x%3Dcos%5E2xcos%5E2x%2Bcos%5E4x%3Dcos%5E2x%281%2Bcos%5E2x%29%3Dsinx%281%2Bsinx%29%3Dsinx%2Bsin%5E2x%3D1cos%5E2x%281%2Bcos%5E2x%29%3Dsinx%281%2Bsinx%29%E6%80%8E%E4%B9%88%E6%9D%A5%E7%9A%84%3F)
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