若实数x,y满足(1+i)x+(1-i)y=2,求x*y的值.
来源:学生作业帮助网 编辑:作业帮 时间:2024/12/02 02:06:06
x){ѽyϦnЩ|{m0Ԭ0Ԭ5yB
{lХ_`gCm*bڕڙZP'^4< ԭ5q//~o:DʶzdR@~qAb6`6ځHC"t#51$@9\.5Tx6g6+ذ갹QVlPPPЮԮԭ̄i
A&XQpӃ "V ԆZ
若实数x,y满足(1+i)x+(1-i)y=2,求x*y的值.
若实数x,y满足(1+i)x+(1-i)y=2,求x*y的值.
若实数x,y满足(1+i)x+(1-i)y=2,求x*y的值.
(1+i)x+(1-i)y=2
x+y+i*(x-y)=2
从而有
x+y=2
x-y=0
联立解得
x=y=1
所以x*y=1
(1+i)x+(1-i)y=2
=>
X+Y+i*(X-Y)=2
=>
X+Y=2
X-Y=0
联立解得
X=Y=1 望采纳 谢谢~
∵(1+i)x+(1-i)y=2
x+xi+y-yi=2
(x+y)+(x-y)i=2+0i
∴x+y=2,x-y=0
∴x=y=1
故xy=1
若实数x,y满足(1+i)x+(1-i)y=2,求x*y的值.
设i为虚数单位,若(x+i)(1-i=y)则实数x.y满足什么条件?
关于高中虚数已知i是虚数单位,实数x、y满足(x+i)i+y=1+2i,则x-y的值
实数X、Y满足(1-i)x+(1+i)y=2,则xy的值是?
已知实数x 纯虚数y 满足(2x-1)+(3-y) i=y-i 求x y的值
已知x为实数,y是纯虚数,且满足(2x-1)+(3-y)i=y-i,则x=____,y=____
已知实数x,纯虚数y满足(2x-1)+(3-y) i=y-i.求x,y的值
已知x是实数,y是虚数,且满足(2x-1)+i=y-(3-y)i,求x和y
若x是实数,y是纯虚数且满足2x-1+2i=y.则x=?,y=?怎么写啊
若实数xy满足x-y+1
若实数x,y是满足1
已知i是洗车虚数单位若实数x,y满足(1+i)(x+yi)=(1-i)(2+3i)试判断点P(x,y)所在的象限
求满足下列条件的实数x,y的值:(x/1-i)+(y/1-2i)=5/1-3i
若实数x,y满足x+y+(x-y)i=2,则xy的值等于
已知x,y为实数,i为虚数单位.若x/(1-i)+y/(1-2i)=5/(1-3i),则x+y的值为?
已知2x-1+(y+1)i=x-y+(-x-y)i,求实数x,y的值
若实数x,y满足x-y+1》=0,x+y>=0,x
若实数x,y满足x-y+1>=0,x+y>=0,x