数列{an}满足an+an+1=1/2(n属于N*),a1=-1/2,Sn是{an}的前n项和,则S2011=_
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/08 14:13:37
![数列{an}满足an+an+1=1/2(n属于N*),a1=-1/2,Sn是{an}的前n项和,则S2011=_](/uploads/image/z/9112192-16-2.jpg?t=%E6%95%B0%E5%88%97%7Ban%7D%E6%BB%A1%E8%B6%B3an%2Ban%2B1%3D1%2F2%28n%E5%B1%9E%E4%BA%8EN%2A%29%2Ca1%3D-1%2F2%2CSn%E6%98%AF%7Ban%7D%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8C%2C%E5%88%99S2011%3D_)
xMj0l,L L,ݔ,\p~bHK7֍%9A{
u.$s9j˴#,Cot}?V}Ebn=ipv!nta 4ef2DXϚe]bsTmMH4)81ۃ 'U~H`| Ϩ+^՛RO_m jb찝_?n֜%w`q
2)~&="-̤x-&|(
数列{an}满足an+an+1=1/2(n属于N*),a1=-1/2,Sn是{an}的前n项和,则S2011=_
数列{an}满足an+an+1=1/2(n属于N*),a1=-1/2,Sn是{an}的前n项和,则S
2011=_
数列{an}满足an+an+1=1/2(n属于N*),a1=-1/2,Sn是{an}的前n项和,则S2011=_
a(n) + a(n+1)=1/2 =>任意连续两数是互补成0.5的互补数
a1=-0.5 =>a1的补数 a2=1
a3跟a1同为a2的补数=>a3=a1
如此类推,a(单数)=-0.5
相似地,a(双数)=1
s2011=(a1+...+a2011)+(a2+...+a2010)=1006*(-0.5)+1005*1=502
数列{an}满足a1=1 an+1=2n+1an/an+2n
数列{an}满足a1=1,且an=an-1+3n-2,求an
数列an满足a1=2,an+1=4an+9,则an=?
已知数列{an}满足an+1=2an+3.5^n,a1=6.求an
数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an
数列an满足a1=2,an+1=an²求an
数列an满足a1=2,an+1=an²求an
已知数列{an}满足a1=1 an+1=an/(3an+1) 则球an
已知数列an满足 a1=1/2,an+1=3an/an+3求证1/an为等差数列已知数列an满足 a1=1/2,an+1=3an/an+3求证1/an为等差数列
已知数列an满足a1=1,1/an+1=根号1/an^2+2,an>0,求an
数列{an}满足:a1=1,an>0,an+1^2-an^2=1,那么an
数列{an}满足:a1=1,an>0,an+1^2-an^2=1,那么an
已知数列{an}满足a1=1,a2=3,an+2=3an+1-2an求an
知数列{an}满足a1=-2,an+1(下标)=2+2an/(1-an),则an为?
已知数列{an}满足a1=1,an+1 -an+2an+1•an=0求通项
已知数列{an}满足a1=2,an+1-an=an+1*an,那么a31等于
数列an满足,a1=8且8an+1an-16an+1+2an+5=0
数列an满足an+1=根号(an^2+1)+an,a1=a>0,求an通项公式