如图四边形ABCD中,AC平分∠BAD,CE⊥AB于E,AE=1/2(AD+AB).求∠ADC+∠ABC的度数.
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![如图四边形ABCD中,AC平分∠BAD,CE⊥AB于E,AE=1/2(AD+AB).求∠ADC+∠ABC的度数.](/uploads/image/z/918082-10-2.jpg?t=%E5%A6%82%E5%9B%BE%E5%9B%9B%E8%BE%B9%E5%BD%A2ABCD%E4%B8%AD%2CAC%E5%B9%B3%E5%88%86%E2%88%A0BAD%2CCE%E2%8A%A5AB%E4%BA%8EE%2CAE%EF%BC%9D1%EF%BC%8F2%EF%BC%88AD%2BAB%EF%BC%89.%E6%B1%82%E2%88%A0ADC%EF%BC%8B%E2%88%A0ABC%E7%9A%84%E5%BA%A6%E6%95%B0.)
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