已知a,b互为相反数,c,d互为倒数,e的绝对值是2,且x=3a+3b/e+2cd+1/2e^2,求9x^2+[4x^2-3x^2-2(x^2-3x)]值

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已知a,b互为相反数,c,d互为倒数,e的绝对值是2,且x=3a+3b/e+2cd+1/2e^2,求9x^2+[4x^2-3x^2-2(x^2-3x)]值
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已知a,b互为相反数,c,d互为倒数,e的绝对值是2,且x=3a+3b/e+2cd+1/2e^2,求9x^2+[4x^2-3x^2-2(x^2-3x)]值
已知a,b互为相反数,c,d互为倒数,e的绝对值是2,且x=3a+3b/e+2cd+1/2e^2,
求9x^2+[4x^2-3x^2-2(x^2-3x)]值

已知a,b互为相反数,c,d互为倒数,e的绝对值是2,且x=3a+3b/e+2cd+1/2e^2,求9x^2+[4x^2-3x^2-2(x^2-3x)]值
a,b互为相反数,c,d互为倒数,e的绝对值是2
a+b=0
cd=1
e²=4
e=±2
x=3a+3b/e+2cd+1/2e^2
x=0+2+2
x=4
9x^2+[4x^2-3x^2-2(x^2-3x)]
=9x²+4x²-3x²-2x²+6x
=10x²+6x
=160+24
=184

X = (3a + 3b)/e + 2 + 2 = 4
9x^2+[4x^2-3x^2-2(x^2-3x)] = 9x^2+4x^2-3x^2-2x^2-6x = 8x^2-6x = 2X(4x - 3) = 104

题意得
a+b=0 cd=1 |e|=2
∴x=2+1/2*2^2=4
故原式=9x^2+4x^2-3x^2-2x^2+6x=8x^2+6x=8*4^2+6*4=128+24=152