(1/a+b)-(1/a-b)=? @□@; p~l~ea~~se~~
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(1/a+b)-(1/a-b)=? @□@; p~l~ea~~se~~
(1/a+b)-(1/a-b)=? @□@; p~l~ea~~se~~
(1/a+b)-(1/a-b)=? @□@; p~l~ea~~se~~
答:
1/(a+b)-1/(a-b)
=(a-b)/[(a+b)(a-b)]-(a+b)/[(a+b)(a-b)]
=[(a-b)-(a+b)]/(a^2-b^2)
=-2b/(a^2-b^2)
=2b/(b^2-a^2)