已知x^2+4y^2-4x+4y+5=0,求(补充如下)x^4-y^4/2x^2-xy/xy-y^2÷(x^2+y^2/y)的值
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已知x^2+4y^2-4x+4y+5=0,求(补充如下)x^4-y^4/2x^2-xy/xy-y^2÷(x^2+y^2/y)的值
已知x^2+4y^2-4x+4y+5=0,求(补充如下)
x^4-y^4/2x^2-xy/xy-y^2÷(x^2+y^2/y)的值
已知x^2+4y^2-4x+4y+5=0,求(补充如下)x^4-y^4/2x^2-xy/xy-y^2÷(x^2+y^2/y)的值
x²+4y²-4x+4y+5=0
(x²-4x+4)+(4y²+4y+1)=0
(x-2)²+(2y+1)²=0
x-2=0 x=2
2y+1=0 y=-1/2
下面自己做
x^2+4y^2-4x+4y+5=(x-2)^2+(2y-1)^2-5+5
那么(x-2)^2+(2y-1)^2=0 x=2,y=-1/2
x^4-y^4/2x^2-xy/xy-y^2÷(x^2+y^2/y)=(x+y)*y/2x=-3/16
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