1、若|a-1|+(b+2)^2=0,A=3a^2-6ab+b^2,B=-a^2-5a,求A-B的值.(12分)

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/28 23:08:01
1、若|a-1|+(b+2)^2=0,A=3a^2-6ab+b^2,B=-a^2-5a,求A-B的值.(12分)
xPA0TJ=xIC1`xQ_p!9feWq^\1ӅL!\{qQ)T%!P^8,MaV)943{>3?̷8gUg!h*2t1}`B4'-:#|R4bAH]ds

1、若|a-1|+(b+2)^2=0,A=3a^2-6ab+b^2,B=-a^2-5a,求A-B的值.(12分)
1、若|a-1|+(b+2)^2=0,A=3a^2-6ab+b^2,B=-a^2-5a,求A-B的值.(12分)

1、若|a-1|+(b+2)^2=0,A=3a^2-6ab+b^2,B=-a^2-5a,求A-B的值.(12分)
|a-1|+(b+2)^2=0
所以a-1=0,b+2=0
a=1
b=-2
A-B
=3a^2-6ab+b^2-(-a^2-5a)
=4a^2-6ab+b^2+5a
=4*1^2-6*1*(-2)+(-2)^2+5*1
=4+12+4+5
=25