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已知0
已知0<α<45°,sin(45°-α)=1/3,则cos(45°+α)=?
已知0
cos(45°+a)
=sin[90°-(45°+a)]
=sin(45°-a)
=1/3
sin(45°-α)=1/3
那么cos(45°+α)=cos[90°-(45°-α)]=sin(45°-α)=1/3
cos(45°+α)=sin(90°-(45°+α))=sin(45°-α)=1/3