已知双曲线x²/a²-y²/b²=1(a>0,b>0)求详解,在线等,急~~~~~已知双曲线x²/a²-y²/b²=1(a>0,b>0)的两条渐近线方程为y=(±√3)/3,若顶点到渐近线的距离为1,则双曲线方程为
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![已知双曲线x²/a²-y²/b²=1(a>0,b>0)求详解,在线等,急~~~~~已知双曲线x²/a²-y²/b²=1(a>0,b>0)的两条渐近线方程为y=(±√3)/3,若顶点到渐近线的距离为1,则双曲线方程为](/uploads/image/z/9298683-27-3.jpg?t=%E5%B7%B2%E7%9F%A5%E5%8F%8C%E6%9B%B2%E7%BA%BFx%26%23178%3B%2Fa%26%23178%3B-y%26%23178%3B%2Fb%26%23178%3B%3D1%28a%3E0%2Cb%3E0%29%E6%B1%82%E8%AF%A6%E8%A7%A3%2C%E5%9C%A8%E7%BA%BF%E7%AD%89%2C%E6%80%A5%7E%7E%7E%7E%7E%E5%B7%B2%E7%9F%A5%E5%8F%8C%E6%9B%B2%E7%BA%BFx%26%23178%3B%2Fa%26%23178%3B-y%26%23178%3B%2Fb%26%23178%3B%3D1%28a%3E0%2Cb%3E0%29%E7%9A%84%E4%B8%A4%E6%9D%A1%E6%B8%90%E8%BF%91%E7%BA%BF%E6%96%B9%E7%A8%8B%E4%B8%BAy%3D%28%C2%B1%E2%88%9A3%29%2F3%2C%E8%8B%A5%E9%A1%B6%E7%82%B9%E5%88%B0%E6%B8%90%E8%BF%91%E7%BA%BF%E7%9A%84%E8%B7%9D%E7%A6%BB%E4%B8%BA1%2C%E5%88%99%E5%8F%8C%E6%9B%B2%E7%BA%BF%E6%96%B9%E7%A8%8B%E4%B8%BA)
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已知双曲线x²/a²-y²/b²=1(a>0,b>0)求详解,在线等,急~~~~~已知双曲线x²/a²-y²/b²=1(a>0,b>0)的两条渐近线方程为y=(±√3)/3,若顶点到渐近线的距离为1,则双曲线方程为
已知双曲线x²/a²-y²/b²=1(a>0,b>0)求详解,在线等,急~~~~~
已知双曲线x²/a²-y²/b²=1(a>0,b>0)的两条渐近线方程为y=(±√3)/3,若顶点到渐近线的距离为1,则双曲线方程为
已知双曲线x²/a²-y²/b²=1(a>0,b>0)求详解,在线等,急~~~~~已知双曲线x²/a²-y²/b²=1(a>0,b>0)的两条渐近线方程为y=(±√3)/3,若顶点到渐近线的距离为1,则双曲线方程为
渐近线方程为y=(±√3)x/3
则:b/a=√3/3
取右顶点(a,0)到渐近线y=(√3)x/3的距离d=(√3)a/2√3=a/2=1
得:a=2,b=2√3/3
所以,方程为:x²/4-y²/(4/3)=1
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双曲线方程可设为:(x+√3y)(x-√3y)=λ
顶点坐标为:(√λ,0),它到渐近线:x+√3y=0的距离为:
d=√λ/2=1
λ=4
所以双曲线方程为:x²/4-3y²/4=1
b^2=4/3,a^2=4