2x=3y+6z+11 3y=2x+6z+11 6z=2x+3y+11 求x y z各是多少
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2x=3y+6z+11 3y=2x+6z+11 6z=2x+3y+11 求x y z各是多少
2x=3y+6z+11 3y=2x+6z+11 6z=2x+3y+11 求x y z各是多少
2x=3y+6z+11 3y=2x+6z+11 6z=2x+3y+11 求x y z各是多少
由(1)得
2x-3y-6z=11 (4)
由(2)得
2x-3y+6z=-11 (5)
由(3)得
2x+3y-6z=-11 (6)
(4)-(5)得
-12z=22
z=-11/6
(5)+(6)得
4x=-22
∴x=-11/2
(4)-(6)得
-6y=22
∴y=-11/3
∴方程组的解是
x=-11/2
y=-11/3
z=-11/6
x=-11/2 y=-11/3 z=-11/6
x+y+z=6 x+2y+3z=14 y+1=z
2x+3y+z=11,x+y+z=6,3x-y-z=-2求解
2x+3y+z=11,3x+y-z=2,x+y+z=6求解
如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,
1.{x:y:z=3:4:5 2x+3y-5z=-142.{x-y-z=-1 3x+5y+7z=11 4x-y+2z=-13.{x+y=1 x+z=0 2x+y+2z=44.{x-y+z=-3 2x-y-z=-2 -3x+y+z=-15.{x-y+z=-3 3x+y-4z=6 2x+y-z=36.{x-2y+5z=16 2x+y-5z=7 2x-y+z=38
3x-y+z=4,2z+3y-z=12,x+y+z=6的解
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
..1.x+y+z=26,2.4y+3z=7,y-z=1,3x+2z=17,x+2y-z=18 9x-7y=173.x-7y+3z=17 4.2x+4y+3z=95x-6y-z=24 3x-2y+5z=113x+7y-2z=1 5x-6y+7z=131.x+y+z=26,y-z=1x+2y-z=18 2.4y+3z=7,3x+2z=11,9x-7y=17 3.x-7y+3z=17 5x-6y-z=24 3x+7y-2z=14.2x+4y+3z=93x-2y+5z=11 5x-6y+7z=13
三元一次方程组 x+y+z=6 x-z=2 2x-y+z=5 三元一次方程组x+y-z=-3 2x+y-3z=-2 3x-y+2z=-11三元一次方程组5z-4y=0 3y-5z=0 2x-y+z=6
若X:Y:Z=5:6:7那么(Y-X):(Y+Z)和(X+2Y+3Z):(3X+2Y+Z)
解三元一次方程组:(1)x+2y+3z=11x-y+4z=10x+3y+2z=2(2)x:y=3:5y:z=5:6x+y+2z=40(3)x+y-z=2y+z-x=4z+x-y=6谢谢!
(1)2X+4Y+3Z=93X-2Y+5Z=115X-6Y+7Z=13(2)X:Y=3:2Y:Z=5:4X+Y+Z=66(3)3X-Y+Z=32X+Y-3Z=11X+Y+Z=13以上3个题目为三元一次方程~
三元一次方程x+y+z=0 4x+2y+z=3 9x+3y+z=6x+y+z=04x+2y+z=3 9x+3y+z=6
(1)X+Y=15,Y+Z=-6,Z+X=7.(2)X+Y=-14,Y+Z=-7,Z+X=9.(3)X+Y=0,Y+Z=-1,Z+X=-1.
2x+4y+2z=6 3x-2y+5z=11
2x-y+2z=6 3x+y-3z=-4 x+y+z=6
2x-3y-z=-6 7x-y+2z=-17 x-y+z=-6