设0
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设0
设0
设0
解a2/x+b2/1-x =(a/x+b/1-x)[x+(1-x)] =a+a(1-x)/x+bx/1-x+b =a+b+a(1-x)/x+bx/1-x ≥a+b+2√a(1-x)/x*bx/1-x =a+b+2√a*b =a+b+2ab =(a+b) 即a2/x+b2/1-x的最小值为(a+b)