对任意x,y属于R,恒有sinx+cosy=2sin(x-y\2+派\4)cos(x+y\2-派\4),则sin13派\24cos5派\24等于
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![对任意x,y属于R,恒有sinx+cosy=2sin(x-y\2+派\4)cos(x+y\2-派\4),则sin13派\24cos5派\24等于](/uploads/image/z/9308055-39-5.jpg?t=%E5%AF%B9%E4%BB%BB%E6%84%8Fx%2Cy%E5%B1%9E%E4%BA%8ER%2C%E6%81%92%E6%9C%89sinx%2Bcosy%3D2sin%28x-y%5C2%2B%E6%B4%BE%5C4%29cos%28x%2By%5C2-%E6%B4%BE%5C4%29%2C%E5%88%99sin13%E6%B4%BE%5C24cos5%E6%B4%BE%5C24%E7%AD%89%E4%BA%8E)
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对任意x,y属于R,恒有sinx+cosy=2sin(x-y\2+派\4)cos(x+y\2-派\4),则sin13派\24cos5派\24等于
对任意x,y属于R,恒有sinx+cosy=2sin(x-y\2+派\4)cos(x+y\2-派\4),则sin13派\24cos5派\24等于
对任意x,y属于R,恒有sinx+cosy=2sin(x-y\2+派\4)cos(x+y\2-派\4),则sin13派\24cos5派\24等于
x-y\2+派\4=13派\24
x+y\2-派\4=5派\24
解得x=3π/4,y= π/6
对任意x,y属于R,恒有sinx+cosy=2sin(x-y\2+派\4)cos(x+y\2-派\4),所以
sin13派\24cos5派\24
= (sin3π/4+cosπ/6 )/2
= (√3+ √2 )/4