2x^2-7x 5=0 (x-2/X+2)-(10Y+5/X^2-4)=1 (2X-3)^2-2X+3=0 (X+1)(X-3)>=(X+1)^22x^2-7x 5=0 (x-2/X+2)-(10Y+5/X^2-4)=1 (2X-3)^2-2X+3=0 (X+1)(X-3)>=(X+1)^2用十字相乘法.
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![2x^2-7x 5=0 (x-2/X+2)-(10Y+5/X^2-4)=1 (2X-3)^2-2X+3=0 (X+1)(X-3)>=(X+1)^22x^2-7x 5=0 (x-2/X+2)-(10Y+5/X^2-4)=1 (2X-3)^2-2X+3=0 (X+1)(X-3)>=(X+1)^2用十字相乘法.](/uploads/image/z/9314030-38-0.jpg?t=2x%5E2-7x+5%3D0+%28x-2%2FX%2B2%29-%2810Y%2B5%2FX%5E2-4%29%3D1+%282X-3%29%5E2-2X%2B3%3D0+%28X%2B1%29%28X-3%29%3E%3D%28X%2B1%29%5E22x%5E2-7x+5%3D0+%28x-2%2FX%2B2%29-%2810Y%2B5%2FX%5E2-4%29%3D1+%282X-3%29%5E2-2X%2B3%3D0+%28X%2B1%29%28X-3%29%3E%3D%28X%2B1%29%5E2%E7%94%A8%E5%8D%81%E5%AD%97%E7%9B%B8%E4%B9%98%E6%B3%95.)
2x^2-7x 5=0 (x-2/X+2)-(10Y+5/X^2-4)=1 (2X-3)^2-2X+3=0 (X+1)(X-3)>=(X+1)^22x^2-7x 5=0 (x-2/X+2)-(10Y+5/X^2-4)=1 (2X-3)^2-2X+3=0 (X+1)(X-3)>=(X+1)^2用十字相乘法.
2x^2-7x 5=0 (x-2/X+2)-(10Y+5/X^2-4)=1 (2X-3)^2-2X+3=0 (X+1)(X-3)>=(X+1)^2
2x^2-7x 5=0
(x-2/X+2)-(10Y+5/X^2-4)=1
(2X-3)^2-2X+3=0
(X+1)(X-3)>=(X+1)^2
用十字相乘法.
2x^2-7x 5=0 (x-2/X+2)-(10Y+5/X^2-4)=1 (2X-3)^2-2X+3=0 (X+1)(X-3)>=(X+1)^22x^2-7x 5=0 (x-2/X+2)-(10Y+5/X^2-4)=1 (2X-3)^2-2X+3=0 (X+1)(X-3)>=(X+1)^2用十字相乘法.
1. 2x²-7x+5 = 0
2 -5
1 -1
(2x-5)(x-1) = 0 , x = 5/2 , 1
2. 怎么有个Y?
3. (2x-3)²-2x+3 = 0
(2x-3)²-(2x-3) = 0
(2x-3)(2x-4) = 0
x = 3/2 ,2
4.(x+1)(x+3) ≥ (x+1)²
(x+1)(x+3) - (x+1)² ≥ 0
(x+1)(x+3-x-1) ≥ 0
2(x+1) ≥ 0
x ≥ -1
1. 2x²-7x+5 = 0
2 -5
1 -1
(2x-5)(x-1) = 0 , x = 5/2 , 1
2. (2x-3)²-2x+3 = 0
(2x-3)²-(2x-3) = 0
(2x-3)(2x-4) = 0
x =...
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1. 2x²-7x+5 = 0
2 -5
1 -1
(2x-5)(x-1) = 0 , x = 5/2 , 1
2. (2x-3)²-2x+3 = 0
(2x-3)²-(2x-3) = 0
(2x-3)(2x-4) = 0
x = 3/2 ,2
3.(x+1)(x+3) ≥ (x+1)²
(x+1)(x+3) - (x+1)² ≥ 0
(x+1)(x+3-x-1) ≥ 0
2(x+1) ≥ 0
x ≥ -1
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