2x^2-5x+m/1的值恒为正数,求m

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2x^2-5x+m/1的值恒为正数,求m
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2x^2-5x+m/1的值恒为正数,求m
2x^2-5x+m/1的值恒为正数,求m

2x^2-5x+m/1的值恒为正数,求m
2x²-5x+m/1恒为正
配方 2x²-5x+m/1=2x²-5x+25/8-25/8+m/1
=(根号2*x-5/2倍根号2)²+m/1-25/8>0
即 m的取值为m>25/8

m>25/8