初二的异分母相加 1/(x-1)(x-2)+1/(x-2)(x-3)

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/29 11:02:21
初二的异分母相加 1/(x-1)(x-2)+1/(x-2)(x-3)
x){1ɮZizl};v-P0BN0І  "}j_`gC5lԭ1igڵz*$ ckХgu OM7BsؤgS׼Xe{]m @~

初二的异分母相加 1/(x-1)(x-2)+1/(x-2)(x-3)
初二的异分母相加 1/(x-1)(x-2)+1/(x-2)(x-3)

初二的异分母相加 1/(x-1)(x-2)+1/(x-2)(x-3)
通分,分母变成(x-1)*(x-2)*(x-3) 分子变成(x-3)+(x-1)=2*(x-2) 化简得2/(x-1)(x-3) 敬请采纳