作业帮(x²+y²-z²+2xy）/(x²-y²+z²-2xz）计算.
来源：学生作业帮助网 编辑：作业帮 时间：2024/09/08 19:37:24
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(x²+y²-z²+2xy）/(x²-y²+z²-2xz）计算.
(x²+y²-z²+2xy）/(x²-y²+z²-2xz）计算.
(x²+y²-z²+2xy）/(x²-y²+z²-2xz）计算.
具体过程是这样的：
原式=[(x²+2xy+y²）-z²]/[(x²-2xz+z²）-y²）]
=[(x+y)²-z²]/[(x-z)²-y²]
=(x+y+z)(x+y-z)/(x-z+y)(x-z-y)
=(x+y+z)/(x-z-y)
(x+y-z)/(x-y+z)
(x+y)^2-Z^2/(x+z)^2-y^2=(x+y+z)(x+y-z)/(x-y+z)(x+y+z)=x+y-z/x-y+z
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看看我的截图