lim(x→1)sinπx╱2(x-1)
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lim(x→1)sinπx╱2(x-1)
lim(x→1)sinπx╱2(x-1)
lim(x→1)sinπx╱2(x-1)
0/0型
分子分母求导
=πcosπx/2
lim(x→1)
=-π/2
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此极限属于0/0型,可用罗比达法则分子分母一阶导数求比值取得
lim(x→1)sinπx╱2(x-1)
=
lim(x→1) πcosπx/2=-π/2
lim(x→1)sinπx╱2(x-1)
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