(-2x^3y^2)^3÷(-1/2x^ny^2)=-mx^7y^p 求m、n、p的值
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(-2x^3y^2)^3÷(-1/2x^ny^2)=-mx^7y^p 求m、n、p的值
(-2x^3y^2)^3÷(-1/2x^ny^2)=-mx^7y^p 求m、n、p的值
(-2x^3y^2)^3÷(-1/2x^ny^2)=-mx^7y^p 求m、n、p的值
利用比较系数与指数的方法.
∵(-2x^3y^2)^3÷[-(1/2)x^ny^2]
=(-8x^9y^6)÷[-(1/2)x^ny^2]
=16x^(9-n)y^4,
∴16x^(9-n)y^4=-mx^7y^p. 显然,要使该式恒等,就需要:
16=-m、9-n=7、4=p,∴m=-16、n=2、p=4.
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