一:椭圆x²/a² +y²/b²=1(a>b>0)与直线x+y-1=0相较于两点p Q.且op⊥OQ(o为原点)(1)求证:1/a² +1/b²为定值(2)若离心率e∈[√3/3,√2/2],求椭圆长轴的取值范围
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![一:椭圆x²/a² +y²/b²=1(a>b>0)与直线x+y-1=0相较于两点p Q.且op⊥OQ(o为原点)(1)求证:1/a² +1/b²为定值(2)若离心率e∈[√3/3,√2/2],求椭圆长轴的取值范围](/uploads/image/z/9444650-50-0.jpg?t=%E4%B8%80%EF%BC%9A%E6%A4%AD%E5%9C%86x%26sup2%3B%EF%BC%8Fa%26sup2%3B+%2By%26sup2%3B%EF%BC%8Fb%26sup2%3B%3D1%EF%BC%88a%EF%BC%9Eb%EF%BC%9E0%EF%BC%89%E4%B8%8E%E7%9B%B4%E7%BA%BFx%2By-1%3D0%E7%9B%B8%E8%BE%83%E4%BA%8E%E4%B8%A4%E7%82%B9p+Q.%E4%B8%94op%E2%8A%A5OQ%EF%BC%88o%E4%B8%BA%E5%8E%9F%E7%82%B9%EF%BC%89%EF%BC%881%EF%BC%89%E6%B1%82%E8%AF%81%EF%BC%9A1%EF%BC%8Fa%26sup2%3B+%2B1%EF%BC%8Fb%26sup2%3B%E4%B8%BA%E5%AE%9A%E5%80%BC%EF%BC%882%EF%BC%89%E8%8B%A5%E7%A6%BB%E5%BF%83%E7%8E%87e%E2%88%88%5B%E2%88%9A3%EF%BC%8F3%2C%E2%88%9A2%EF%BC%8F2%5D%2C%E6%B1%82%E6%A4%AD%E5%9C%86%E9%95%BF%E8%BD%B4%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4)
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