作业帮(x^2-3x+2)^2+(x^2-3x+2)(3x^2-2x-1)+(3x^2-2x-1)^2=(4x^2-5x+1)^2要过程!急
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(x^2-3x+2)^2+(x^2-3x+2)(3x^2-2x-1)+(3x^2-2x-1)^2=(4x^2-5x+1)^2要过程!急
(x^2-3x+2)^2+(x^2-3x+2)(3x^2-2x-1)+(3x^2-2x-1)^2=(4x^2-5x+1)^2要过程!急
(x^2-3x+2)^2+(x^2-3x+2)(3x^2-2x-1)+(3x^2-2x-1)^2=(4x^2-5x+1)^2要过程!急
x=1或x=2 把第一项和第二项提取公因式,得出的结果跟原等式右边的部分又有公因式可以提,然后可以得出很简单的结果：x^2-3x+2=0 .后面的楼猪可以解了吧.
(x²-3x+2)²+(x²-3x+2)(3x²-2x-1)+(3x²-2x-1)²
=[(x-1)(x-2)]²+(x-1)(x-2)(x-1)(3x+1)+[(x-1)(3x+1)]²
=(x-1)²[(x-2)²+(x-2)(3x+1)+(3x+1)²]
=(...
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(x²-3x+2)²+(x²-3x+2)(3x²-2x-1)+(3x²-2x-1)²
=[(x-1)(x-2)]²+(x-1)(x-2)(x-1)(3x+1)+[(x-1)(3x+1)]²
=(x-1)²[(x-2)²+(x-2)(3x+1)+(3x+1)²]
=(x-1)²(x²-4x+4+3x²-5x-2+9x²+6x+1)
=(x-1)²(13x²-3x+3)
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