求证:tanx^2-sinx^2=tanx^2sinx^2
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/03 05:35:55
x){{f$U[ a̅@6IED/!ۗط(lhna]_e"DjTi"3ĔEk"EWftU@gCYO7qĽ/xo:з6yv ҟ
求证:tanx^2-sinx^2=tanx^2sinx^2
求证:tanx^2-sinx^2=tanx^2sinx^2
求证:tanx^2-sinx^2=tanx^2sinx^2
左边=sin²x/cos²x-sin²x
=sin²x(1/cos²x-1)
=sin²x(1-cos²x)/cos²x
=sin²x*sin²x/cos²x
=sin²xtan²x=右边
命题得证
求证:tanx^2-sinx^2=tanx^2sinx^2
3sinX=sin(2X+Y) 求证:tan(X+Y)=2tanX
求证:(sinx+cosx)(1-tanx)=2sinx/tan2x
求证:tan(x/2+π/4)+tan(x/2-π/4)=2tanx
tanx/[根号(1+tan^2)]化简 为什么是sinx?RT
如何用tan x/2表示sinx ,cosx ,tanx
tan半角公式为啥tanx/2=(1-cosx)/sinx?
求证:(1+sinx+cosx)/(1+sinx-cosx)-(1+sinx-cosx)/(1+sinx+cosx)=2/tanx
已知cosx-sinx=√2sinx,求证(cosx-sinx)/(cosx+sinx)=tanx
cosx-sinx=根号2sinx,求证tanx=cosx-sinx/cosx+sinx谢谢了,
求证:secx - tanx = tan(π/4 - x/2)
求值域.①y=2sinxcos^2x/1+sinx ②y=tan^2x-tanx+1/tan^2x+tanx+1
提问数学难题求证:sin^2x*tanx+cos^2x/tanx+2sinx*cosx=tanx+1/tanx
sinx×2sinx-tanx×sin2x
(sinx+cosx)(tan^2x+1/tanx)=1/cosx+1/sinx
求证:x为锐角,sinx+tanx大于2x
+tan(sinx)sin(tanx)什么意思limx→0+tan(sinx)sin(tanx)原式=limx→0+[sec(sinx)]^2cosx2tan(sinx)cos(tanx)sec2x2sin(tanx) (用罗比塔法则)=limx→0+sec2(sinx)cosxcos(tanx)sec2x•limx→0+sin(tanx)tan(sinx) (分离非零极限乘积
求证:1-2cosXcosX/cos平方X-sin平方X=1-tan/1+tanX