如图,AD⊥BC,CE⊥AB,垂足分别是D.E,AD交CE于点F,AD=EC.求证AE=CD
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![如图,AD⊥BC,CE⊥AB,垂足分别是D.E,AD交CE于点F,AD=EC.求证AE=CD](/uploads/image/z/9459203-59-3.jpg?t=%E5%A6%82%E5%9B%BE%2CAD%E2%8A%A5BC%2CCE%E2%8A%A5AB%2C%E5%9E%82%E8%B6%B3%E5%88%86%E5%88%AB%E6%98%AFD.E%2CAD%E4%BA%A4CE%E4%BA%8E%E7%82%B9F%2CAD%3DEC.%E6%B1%82%E8%AF%81AE%3DCD)
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如图,AD⊥BC,CE⊥AB,垂足分别是D.E,AD交CE于点F,AD=EC.求证AE=CD
如图,AD⊥BC,CE⊥AB,垂足分别是D.E,AD交CE于点F,AD=EC.求证AE=CD
如图,AD⊥BC,CE⊥AB,垂足分别是D.E,AD交CE于点F,AD=EC.求证AE=CD
证明:∵AD⊥BC,CE⊥AB
∴△AEC和△CAD是直角三角形
∵在RT△AEC和RT△CAD中
AD=AE,AC=CA
∴RT△AEC≌RT△CAD
∴AE=CD