lim x趋向0[e^(x^2)-e^(2-2cosx)]/x^4 答案是1/12

来源：学生作业帮助网 编辑：作业帮 时间：2024/11/17 08:23:08
lim x趋向0[e^(x^2)-e^(2-2cosx)]/x^4 答案是1/12
x)Ux鄉ѩqqF@H(9B3V"D)v

lim x趋向0[e^(x^2)-e^(2-2cosx)]/x^4 答案是1/12
lim x趋向0[e^(x^2)-e^(2-2cosx)]/x^4 答案是1/12

lim x趋向0[e^(x^2)-e^(2-2cosx)]/x^4 答案是1/12
lim(x→0) [e^(x^2)-e^(2-2cosx)]/x^4
=lim(x→0) [e^(x^2)-e^2/e^(2cosx)]/x^4
=lim(x→0) [e^(x^2)*e^(2cosx)-e^2]/[e^(2cosx)*x^4]
=lim(x→0) [e^(x^2)*e^(2cosx)-e^2]/[e^2*x^4]
=lim(x→0) [e^(x^2+2cosx)-e^2]/[e^2*x^4] (0/0)
=lim(x→0) [e^(x^2+2cosx)*(2x-2sinx)]/[4e^2*x^3]
=lim(x→0) [e^2*(2x-2sinx)]/[4e^2*x^3]
=lim(x→0) (x-sinx)/[2x^3] (0/0)
=lim(x→0) (1-cosx)/(6x^2)
=lim(x→0) (x^2/2)/(6x^2)
=1/12

lim(x趋向0）(e^x-e^-x)/x lim(x趋向0) e^x+2= lim ln(e^sinx) x趋向0 lim趋向0时,e^x-e^-1/X lim(x趋向0）(e^x-x^-x)/x 求极限lim （e^x）- (e^-x) -2x / (tanx-x) x趋向于0 lim ln(1+2x)/e^x x趋向于0 e^x lim(x趋向0)(e-e^cosx)/ln(1+x2) lim e-e^cosx除以xsinx x趋向0 利用洛必达法则 lim趋向于0 求[(e^x)+(e^-x)-2]/4x^2 lim e∧x+e∧-x/cosx (x趋向于0)为什么等于2呀 x趋向0 lim [ ln (1-x) / (e ^ x-1 ) ] 求lim x趋向于0(e^x-x-1) lim(1+e^1/x)^x,x趋向于+0 lim(x趋向0)(e-e^cosx)/(√1+x^2的3次方-1) lim(x趋向于0)e^sinx/x lim(e^x-cosx)/xsinx x趋向0 lim(X趋向0)e^(-1)/x^100等于多少