1.如图,AB=DF,AC=DE,BE=FC,求证;∠B=∠F.2.如图,在△ABC中,∠ACB=90°,DE是AB的垂直平分线,∠CAE :∠EAB=4 :1,求∠B的度数.3.已知,△ABC中,AB=AC,D点在AB上,E点在AC的延长线上,且BD=CE,连接DE,交BC于F,求证:DF=
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![1.如图,AB=DF,AC=DE,BE=FC,求证;∠B=∠F.2.如图,在△ABC中,∠ACB=90°,DE是AB的垂直平分线,∠CAE :∠EAB=4 :1,求∠B的度数.3.已知,△ABC中,AB=AC,D点在AB上,E点在AC的延长线上,且BD=CE,连接DE,交BC于F,求证:DF=](/uploads/image/z/9499323-3-3.jpg?t=1.%E5%A6%82%E5%9B%BE%2CAB%3DDF%2CAC%3DDE%2CBE%3DFC%2C%E6%B1%82%E8%AF%81%EF%BC%9B%E2%88%A0B%3D%E2%88%A0F.2.%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2C%E2%88%A0ACB%3D90%C2%B0%2CDE%E6%98%AFAB%E7%9A%84%E5%9E%82%E7%9B%B4%E5%B9%B3%E5%88%86%E7%BA%BF%2C%E2%88%A0CAE+%EF%BC%9A%E2%88%A0EAB%3D4+%EF%BC%9A1%2C%E6%B1%82%E2%88%A0B%E7%9A%84%E5%BA%A6%E6%95%B0.3.%E5%B7%B2%E7%9F%A5%2C%E2%96%B3ABC%E4%B8%AD%2CAB%3DAC%2CD%E7%82%B9%E5%9C%A8AB%E4%B8%8A%2CE%E7%82%B9%E5%9C%A8AC%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%B8%8A%2C%E4%B8%94BD%3DCE%2C%E8%BF%9E%E6%8E%A5DE%2C%E4%BA%A4BC%E4%BA%8EF%2C%E6%B1%82%E8%AF%81%EF%BC%9ADF%3D)
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