正方形ABCD,若直角三角板的直角顶点P在正方形对角线AC上移动,两直角边分别交AD,AB于MN两点.(1)求证:PM的平方等于PQ乘以PA(2)点Q是AP与MN的交点,PQ等于m分之n乘以PN求三角形PAN与PQN面积之比
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/03 22:03:54
![正方形ABCD,若直角三角板的直角顶点P在正方形对角线AC上移动,两直角边分别交AD,AB于MN两点.(1)求证:PM的平方等于PQ乘以PA(2)点Q是AP与MN的交点,PQ等于m分之n乘以PN求三角形PAN与PQN面积之比](/uploads/image/z/9501436-28-6.jpg?t=%E6%AD%A3%E6%96%B9%E5%BD%A2ABCD%2C%E8%8B%A5%E7%9B%B4%E8%A7%92%E4%B8%89%E8%A7%92%E6%9D%BF%E7%9A%84%E7%9B%B4%E8%A7%92%E9%A1%B6%E7%82%B9P%E5%9C%A8%E6%AD%A3%E6%96%B9%E5%BD%A2%E5%AF%B9%E8%A7%92%E7%BA%BFAC%E4%B8%8A%E7%A7%BB%E5%8A%A8%2C%E4%B8%A4%E7%9B%B4%E8%A7%92%E8%BE%B9%E5%88%86%E5%88%AB%E4%BA%A4AD%2CAB%E4%BA%8EMN%E4%B8%A4%E7%82%B9.%EF%BC%881%EF%BC%89%E6%B1%82%E8%AF%81%EF%BC%9APM%E7%9A%84%E5%B9%B3%E6%96%B9%E7%AD%89%E4%BA%8EPQ%E4%B9%98%E4%BB%A5PA%EF%BC%882%EF%BC%89%E7%82%B9Q%E6%98%AFAP%E4%B8%8EMN%E7%9A%84%E4%BA%A4%E7%82%B9%2CPQ%E7%AD%89%E4%BA%8Em%E5%88%86%E4%B9%8Bn%E4%B9%98%E4%BB%A5PN%E6%B1%82%E4%B8%89%E8%A7%92%E5%BD%A2PAN%E4%B8%8EPQN%E9%9D%A2%E7%A7%AF%E4%B9%8B%E6%AF%94)
xSj@[&V1/%ƟcL(lP+$6-(-fp3Vij
m,s9sekF~ͬ?Wo=g]eot$Z*7bzmARrYO-bѻ59>[}ьΣ)nXY':/n^'cjH_My<(EWSB9Id<~9"0(%_^E2Y/^VU~X0bS7?{`2?O
:)f*
t05*buZQw-/]q"U*f
|IpԄ$6Hވ.T|\c<%6G3i`Hc9n=P7u8aP]e*)%