已知三棱柱ABC—A1B1C1为正三棱柱,D是中点.(1)求证:平面BDC1⊥平面A1ACC1(2)求证:AB1平行平面DBC1
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![已知三棱柱ABC—A1B1C1为正三棱柱,D是中点.(1)求证:平面BDC1⊥平面A1ACC1(2)求证:AB1平行平面DBC1](/uploads/image/z/9512974-46-4.jpg?t=%E5%B7%B2%E7%9F%A5%E4%B8%89%E6%A3%B1%E6%9F%B1ABC%E2%80%94A1B1C1%E4%B8%BA%E6%AD%A3%E4%B8%89%E6%A3%B1%E6%9F%B1%2CD%E6%98%AF%E4%B8%AD%E7%82%B9.%EF%BC%881%EF%BC%89%E6%B1%82%E8%AF%81%EF%BC%9A%E5%B9%B3%E9%9D%A2BDC1%E2%8A%A5%E5%B9%B3%E9%9D%A2A1ACC1%282%29%E6%B1%82%E8%AF%81%EF%BC%9AAB1%E5%B9%B3%E8%A1%8C%E5%B9%B3%E9%9D%A2DBC1)
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