△ABC中,AB边的高为CD,向量CB= a,向量CA= b,a•b = 0,| a | = 1,| b | = 2,则向量AD=(A)1/3a -1/3b (B)2/3a -2/3b (C)3/5a -3/5b (D) 4/5a -4/5b 最好把解题思路
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![△ABC中,AB边的高为CD,向量CB= a,向量CA= b,a•b = 0,| a | = 1,| b | = 2,则向量AD=(A)1/3a -1/3b (B)2/3a -2/3b (C)3/5a -3/5b (D) 4/5a -4/5b 最好把解题思路](/uploads/image/z/954855-63-5.jpg?t=%E2%96%B3ABC%E4%B8%AD%2CAB%E8%BE%B9%E7%9A%84%E9%AB%98%E4%B8%BACD%2C%E5%90%91%E9%87%8FCB%3D+a%2C%E5%90%91%E9%87%8FCA%3D+b%2Ca%26%238226%3Bb+%3D+0%2C%7C+a+%7C+%3D+1%2C%7C+b+%7C+%3D+2%2C%E5%88%99%E5%90%91%E9%87%8FAD%3D%28A%291%2F3a+-1%2F3b+%28B%292%2F3a+-2%2F3b+%28C%293%2F5a+-3%2F5b+%28D%29+4%2F5a+-4%2F5b+%E6%9C%80%E5%A5%BD%E6%8A%8A%E8%A7%A3%E9%A2%98%E6%80%9D%E8%B7%AF)
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