编写c程序,计算并输出表达式S=(a-b)/sqrt(a+b)的值.其中a和c的值从键盘出入.#include #include void main() { int a,b,m; double s; printf("Please Input 2 number:\n"); scanf("%d,%d",&a,&b); do { m=(a+b); s=(double)((a-b)/sqrt(m));
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/15 01:49:58
![编写c程序,计算并输出表达式S=(a-b)/sqrt(a+b)的值.其中a和c的值从键盘出入.#include #include void main() { int a,b,m; double s; printf(](/uploads/image/z/955640-56-0.jpg?t=%E7%BC%96%E5%86%99c%E7%A8%8B%E5%BA%8F%2C%E8%AE%A1%E7%AE%97%E5%B9%B6%E8%BE%93%E5%87%BA%E8%A1%A8%E8%BE%BE%E5%BC%8FS%3D%EF%BC%88a-b%EF%BC%89%2Fsqrt%28a%2Bb%29%E7%9A%84%E5%80%BC.%E5%85%B6%E4%B8%ADa%E5%92%8Cc%E7%9A%84%E5%80%BC%E4%BB%8E%E9%94%AE%E7%9B%98%E5%87%BA%E5%85%A5.%23include+%23include+void+main%28%29+%7B+int+a%2Cb%2Cm%3B+double+s%3B+printf%28%22Please+Input+2+number%3A%5Cn%22%29%3B+scanf%28%22%25d%2C%25d%22%2C%26a%2C%26b%29%3B+do+%7B+m%3D%28a%2Bb%29%3B+s%3D%28double%29%28%28a-b%29%2Fsqrt%28m%29%29%3B)
编写c程序,计算并输出表达式S=(a-b)/sqrt(a+b)的值.其中a和c的值从键盘出入.#include #include void main() { int a,b,m; double s; printf("Please Input 2 number:\n"); scanf("%d,%d",&a,&b); do { m=(a+b); s=(double)((a-b)/sqrt(m));
编写c程序,计算并输出表达式S=(a-b)/sqrt(a+b)的值.其中a和c的值从键盘出入.
#include
#include
void main()
{
int a,b,m;
double s;
printf("Please Input 2 number:\n");
scanf("%d,%d",&a,&b);
do
{
m=(a+b);
s=(double)((a-b)/sqrt(m));
}while(m=0);
printf("s=%lf\n",s);
}
我这个程序哪编错了呀?
编写c程序,计算并输出表达式S=(a-b)/sqrt(a+b)的值.其中a和c的值从键盘出入.#include #include void main() { int a,b,m; double s; printf("Please Input 2 number:\n"); scanf("%d,%d",&a,&b); do { m=(a+b); s=(double)((a-b)/sqrt(m));
为什么要do while循环
我帮你改下
#include
#include
void main()
{
int a,b,m;
double s;
printf("Please Input 2 number:\n");
scanf("%d,%d",&a,&b);
m=a+b;
if(m>0)
s=(a-b)/sqrt(m);
printf("s=%lf\n",s);
}
输入的时候要 按a,b格式输入,我帮你试过了可以正常运行的