(m-2n-1)(m-2n-1)=?化简
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/29 03:50:47
x)55ԄѶO{=_`T[RΆD`A[0O3H6iMrtrl~qAb20t
cՔ
-킈`ZT{aOm]tOFvv2ZD1IP:$mdmD$o t"
(m-2n-1)(m-2n-1)=?化简
(m-2n-1)(m-2n-1)=?化简
(m-2n-1)(m-2n-1)=?化简
(m-2n-1)(m-2n-1)
=(m-2n)^2-2(m-2n)+1
=m^2+4n^2-4mn-2m+4n+1
(m-2n-1)(m-2n-1)
=[(m-2n)-1]²
=(m-2n)²-2(m-2n)+1
=m²-4mn+4n²-2m+4n+1
(m-2n-1)(m-2n-1)
=(m-2n-1)²
=m²+(-2n)²+(-1)²+2m×(-2n)+2m×(-1)+2×(-2n)×(-1)
=m²+4n²+1-4mn-2m+4n
就是用完全平方公式(a+b+c)²=a²+b²+c²+2ab+2bc+2ca
(1),(-m-n)(-m+n) (2),(-m+n)(m-n)
C(m,n)=n(n-1)(n-2)...(n-m+1)/m!中的!
(m+n)(m-n)-(1-2n)化简
(m-2n-1)(m-2n-1)=?化简
m,n,(2m-1)/n,(2n-1)/m为正整数,m,n>=2.求m,n
m(m+n)(m-n)-m(m+n)的平方,其中m+n=1,mn=-1/2
因式分解m^2-(n+1)m+n
先化简再求值[(m+n)(m-n)-(m-n)²]÷(2n),其中m=-2,n=-1/2
求集合M={m|m=2n-1,n属于N*,且m
求集合M={m|m=2n-1,n属于N*,且m
求集合M={m/m=2n-1,n属於n*,且M
已知|m-1|+|m+2n|=0 求试|m-n|+|m+n|快
先化简再求值:2m(m-n)-(m+2n)(2m-n),其中m=1,n=-2
(2m+n)(2m-n)+n(2m+n)-8m^2n^3/(2n^3) m=-2分之1,n=2013
若2M=2N 求分式(1+m/n-n/n-m)除以(1-(m/n)-n/n+m)
若2M=2N 求分式(1+m/n-n/n-m)除以(1-(m/n)-n/n+m)
若2m=3n,求分式(1+m/n-n/n-m)除以(1-m/n-n/n+m)的值
若2m=3n,求分式(1+m/n-n/n-m)除以(1-m/n-n/n+m)的值