16X^3-6X^2-4X+1=0 这道方程如何解呢,答案是多少呢看不懂啊,能不能把答案再说一遍,实数范围内就行了.
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/19 05:56:56
![16X^3-6X^2-4X+1=0 这道方程如何解呢,答案是多少呢看不懂啊,能不能把答案再说一遍,实数范围内就行了.](/uploads/image/z/959960-56-0.jpg?t=16X%5E3-6X%5E2-4X%2B1%3D0+%E8%BF%99%E9%81%93%E6%96%B9%E7%A8%8B%E5%A6%82%E4%BD%95%E8%A7%A3%E5%91%A2%2C%E7%AD%94%E6%A1%88%E6%98%AF%E5%A4%9A%E5%B0%91%E5%91%A2%E7%9C%8B%E4%B8%8D%E6%87%82%E5%95%8A%2C%E8%83%BD%E4%B8%8D%E8%83%BD%E6%8A%8A%E7%AD%94%E6%A1%88%E5%86%8D%E8%AF%B4%E4%B8%80%E9%81%8D%2C%E5%AE%9E%E6%95%B0%E8%8C%83%E5%9B%B4%E5%86%85%E5%B0%B1%E8%A1%8C%E4%BA%86.)
16X^3-6X^2-4X+1=0 这道方程如何解呢,答案是多少呢看不懂啊,能不能把答案再说一遍,实数范围内就行了.
16X^3-6X^2-4X+1=0 这道方程如何解呢,答案是多少呢
看不懂啊,能不能把答案再说一遍,实数范围内就行了.
16X^3-6X^2-4X+1=0 这道方程如何解呢,答案是多少呢看不懂啊,能不能把答案再说一遍,实数范围内就行了.
Mathematica求解结果;
In[11]:= Solve[16 x^3 - 6 x^2 - 4 x + 1 == 0,x]
Out[11]= {{x ->
1/8 + (-63 + 4 \[ImaginaryI] Sqrt[1038])^(1/3)/(8 3^(2/3)) + 19/(
8 (3 (-63 + 4 \[ImaginaryI] Sqrt[1038]))^(1/3))},{x ->
1/8 - ((1 + \[ImaginaryI] Sqrt[3]) (-63 +
4 \[ImaginaryI] Sqrt[1038])^(1/3))/(16 3^(2/3)) - (
19 (1 - \[ImaginaryI] Sqrt[3]))/(
16 (3 (-63 + 4 \[ImaginaryI] Sqrt[1038]))^(1/3))},{x ->
1/8 - ((1 - \[ImaginaryI] Sqrt[3]) (-63 +
4 \[ImaginaryI] Sqrt[1038])^(1/3))/(16 3^(2/3)) - (
19 (1 + \[ImaginaryI] Sqrt[3]))/(
16 (3 (-63 + 4 \[ImaginaryI] Sqrt[1038]))^(1/3))}}
\[ImaginaryI]表示复数i