求方程5x²+6xy+2y²-4x+2y+1=0的实数根
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![求方程5x²+6xy+2y²-4x+2y+1=0的实数根](/uploads/image/z/963075-3-5.jpg?t=%E6%B1%82%E6%96%B9%E7%A8%8B5x%26%23178%3B%2B6xy%2B2y%26%23178%3B-4x%2B2y%2B1%3D0%E7%9A%84%E5%AE%9E%E6%95%B0%E6%A0%B9)
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求方程5x²+6xy+2y²-4x+2y+1=0的实数根
求方程5x²+6xy+2y²-4x+2y+1=0的实数根
求方程5x²+6xy+2y²-4x+2y+1=0的实数根
(9x²+6xy+y²)-(4²x+4x+1)+(y²+2y+1)+1=0
(3x+y)²-(2x+1)²+(y+1)²+1=0
(3x+y)²+1+(y+1)²=(2x+1)²
(2x+1)²=1
x=-1
(3x+y)²+(y+1)²=0
y1=3 y2=-1
我的答案正确为啥不选.
还少条件吧 这怎么解
00
题目错误:
5x²-6xy+2y²-4x+2y+1=0
4x²-4xy+y²-2(2x-y)-2xy+y²+x²+1=0
(2x-y)²-2(2x-y)+1-2xy+y²+x²=0
(2x-y-1)²+(x-y)²=0
2x-y-1=0且x=y(或2x-y+1=0,
x=1,y=1