http://hiphotos.baidu.com/%D3%F0%C3%D6%CC%D2%D9%BC%DB%E0/pic/item/9ad9ccd770a2dd1d06088b07.jpghttp://hiphotos.baidu.com/%D3%F0%C3%D6%CC%D2%D9%BC%DB%E0/pic/item/74909e634deba6efe6113a00.jpg这两个图上的题.顺便帮我把这题也做了吧!
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/20 17:09:27
![http://hiphotos.baidu.com/%D3%F0%C3%D6%CC%D2%D9%BC%DB%E0/pic/item/9ad9ccd770a2dd1d06088b07.jpghttp://hiphotos.baidu.com/%D3%F0%C3%D6%CC%D2%D9%BC%DB%E0/pic/item/74909e634deba6efe6113a00.jpg这两个图上的题.顺便帮我把这题也做了吧!](/uploads/image/z/9680153-41-3.jpg?t=http%3A%2F%2Fhiphotos.baidu.com%2F%25D3%25F0%25C3%25D6%25CC%25D2%25D9%25BC%25DB%25E0%2Fpic%2Fitem%2F9ad9ccd770a2dd1d06088b07.jpghttp%3A%2F%2Fhiphotos.baidu.com%2F%25D3%25F0%25C3%25D6%25CC%25D2%25D9%25BC%25DB%25E0%2Fpic%2Fitem%2F74909e634deba6efe6113a00.jpg%E8%BF%99%E4%B8%A4%E4%B8%AA%E5%9B%BE%E4%B8%8A%E7%9A%84%E9%A2%98.%E9%A1%BA%E4%BE%BF%E5%B8%AE%E6%88%91%E6%8A%8A%E8%BF%99%E9%A2%98%E4%B9%9F%E5%81%9A%E4%BA%86%E5%90%A7%EF%BC%81)
http://hiphotos.baidu.com/%D3%F0%C3%D6%CC%D2%D9%BC%DB%E0/pic/item/9ad9ccd770a2dd1d06088b07.jpghttp://hiphotos.baidu.com/%D3%F0%C3%D6%CC%D2%D9%BC%DB%E0/pic/item/74909e634deba6efe6113a00.jpg这两个图上的题.顺便帮我把这题也做了吧!
http://hiphotos.baidu.com/%D3%F0%C3%D6%CC%D2%D9%BC%DB%E0/pic/item/9ad9ccd770a2dd1d06088b07.jpg
http://hiphotos.baidu.com/%D3%F0%C3%D6%CC%D2%D9%BC%DB%E0/pic/item/74909e634deba6efe6113a00.jpg
这两个图上的题.
顺便帮我把这题也做了吧!
http://hiphotos.baidu.com/%D3%F0%C3%D6%CC%D2%D9%BC%DB%E0/pic/item/9ad9ccd770a2dd1d06088b07.jpghttp://hiphotos.baidu.com/%D3%F0%C3%D6%CC%D2%D9%BC%DB%E0/pic/item/74909e634deba6efe6113a00.jpg这两个图上的题.顺便帮我把这题也做了吧!
1.将函数1/(1+X)=1/X +1
整理可得 X^2+X+1=0
b^2-4ac=1-4小于0
无解,即函数不属于集合
2.将函数代入方程得kX+k+b=kX+k+2b
即b=0,k为任意值可使方程成立
3.将函数代入方程求解
(如图)