已知a²+b²-4a-2b+5=0,求√a+√b/√2b-√a-b
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已知a²+b²-4a-2b+5=0,求√a+√b/√2b-√a-b
已知a²+b²-4a-2b+5=0,求√a+√b/√2b-√a-b
已知a²+b²-4a-2b+5=0,求√a+√b/√2b-√a-b
a²+b²-4a-2b+5=0
(a²-4a+4)+(b²-2b+1)=0
(a-2)²+(b-1)²=0
a=2 b=1
√a+√b/√2b-√a-b
=(√2+√1)/(√2-√2-1)
=(√2+1)/(√2-1)
=(√2+1)²/(√2+1)(√2-1)
=(2+2√2+1)/(2-1)
=1.5+√2
+b²-4a-2b+5=0,求√a+√b/