若要将2.5Kg初温为20℃的水加热到80℃至少燃烧多少的液化气?水的比热容是4.2×10三次方J/(Kg.℃)液化气的热值是5.0×10七次方J/m³
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![若要将2.5Kg初温为20℃的水加热到80℃至少燃烧多少的液化气?水的比热容是4.2×10三次方J/(Kg.℃)液化气的热值是5.0×10七次方J/m³](/uploads/image/z/9740198-38-8.jpg?t=%E8%8B%A5%E8%A6%81%E5%B0%862.5Kg%E5%88%9D%E6%B8%A9%E4%B8%BA20%E2%84%83%E7%9A%84%E6%B0%B4%E5%8A%A0%E7%83%AD%E5%88%B080%E2%84%83%E8%87%B3%E5%B0%91%E7%87%83%E7%83%A7%E5%A4%9A%E5%B0%91%E7%9A%84%E6%B6%B2%E5%8C%96%E6%B0%94%3F%E6%B0%B4%E7%9A%84%E6%AF%94%E7%83%AD%E5%AE%B9%E6%98%AF4.2%C3%9710%E4%B8%89%E6%AC%A1%E6%96%B9J%2F%EF%BC%88Kg.%E2%84%83%EF%BC%89%E6%B6%B2%E5%8C%96%E6%B0%94%E7%9A%84%E7%83%AD%E5%80%BC%E6%98%AF5.0%C3%9710%E4%B8%83%E6%AC%A1%E6%96%B9J%2Fm%26sup3%3B)
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若要将2.5Kg初温为20℃的水加热到80℃至少燃烧多少的液化气?水的比热容是4.2×10三次方J/(Kg.℃)液化气的热值是5.0×10七次方J/m³
若要将2.5Kg初温为20℃的水加热到80℃至少燃烧多少的液化气?
水的比热容是4.2×10三次方J/(Kg.℃)
液化气的热值是5.0×10七次方J/m³
若要将2.5Kg初温为20℃的水加热到80℃至少燃烧多少的液化气?水的比热容是4.2×10三次方J/(Kg.℃)液化气的热值是5.0×10七次方J/m³
Q吸=Q放
c水m水Δt水=qV
4.2×10^3J/(Kg·℃)×2.5kg ×(80℃-20℃) =5.0×10^7J/m³ V
解得V=0.0126m³
即,至少燃烧0.0126m³的液化气