解方程组√2x-y=√2,x²-y²/4=1
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解方程组√2x-y=√2,x²-y²/4=1
解方程组√2x-y=√2,x²-y²/4=1
解方程组√2x-y=√2,x²-y²/4=1
你好,
√2x-y=√2,
√2x-y-√2=0
√2(x-1)=y带入x²-y²/4=1,
得4x²-(√2(x-1))²=4
即4x²-2x²+4x-2-4=0
x²+2x-3=0
(x-1)(x+3)=0,得出x1=1,x2=-3
y1=0,y2=-4√2
方程组的有x1y1,x1y2,x2y1,x2y2,希望我的回答对你有帮助
由(1)得
2x-y=2 (3)
由(2)得
(2x+y)(2x-y)=4
∵2x-y=2
∴2x+y=2 (4)
解方程组(3)(4)得
x=1
y=0
检验:x=1,y=0是方程组的解