已知xy满足丨x+y-4a-5丨(x-y-6a+5)²=0,q且4x+5y<9,求a的取值范围
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已知xy满足丨x+y-4a-5丨(x-y-6a+5)²=0,q且4x+5y<9,求a的取值范围
已知xy满足丨x+y-4a-5丨(x-y-6a+5)²=0,q且4x+5y<9,求a的取值范围
已知xy满足丨x+y-4a-5丨(x-y-6a+5)²=0,q且4x+5y<9,求a的取值范围
答:|x+y-4a-5|+(x-y-6a+5)^2=0
绝对值和平方数都是非负数
因此:x+y-4a-5=0
x-y-6a+5=0
解得:
x=5a,y=5-a
因为:4x+5y