若实数xy满足x²+3y²-12y+12=0则y∧x的值
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若实数xy满足x²+3y²-12y+12=0则y∧x的值
若实数xy满足x²+3y²-12y+12=0则y∧x的值
若实数xy满足x²+3y²-12y+12=0则y∧x的值
x²+3y²-12y+12=0
x²+3(y²-4y+4)=0
x²+3(y-2)²=0 且:x²≥0,(y-2)²≥0
所以可得:
x²=0 得:x=0
(y-2)²=0 得:y=2
y^x=2^0=1
〇