已知1/x-1/y=4,求(2x+xy-2y)/(x-2xy-y)的值
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已知1/x-1/y=4,求(2x+xy-2y)/(x-2xy-y)的值
已知1/x-1/y=4,求(2x+xy-2y)/(x-2xy-y)的值
已知1/x-1/y=4,求(2x+xy-2y)/(x-2xy-y)的值
1/x-1/y=4,所以y-x=4xy
1/x-1/y=4
∴y-x=4xy
(2x+xy-2y)/(x-2xy-y)
=[2(x-y)+xy]/[(x-y)-2xy]
=(-8xy+xy)/(-4xy-2xy)
=-7xy/(-6xy)
=7/6