已知1/x-1/y=4,求(2x+xy-2y)/(x-2xy-y)的值

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/16 18:44:43
已知1/x-1/y=4,求(2x+xy-2y)/(x-2xy-y)的值
xQMJ@J)-o&I["$iMʼn".Z P4be$mŕXt1~x|NZ ![<]"jLd *dqn{C iD^&N4uəwpSFd_$A\FEC;CҸw\lbA)e9\=q ¡M aP b7$԰8grH~(VYQfa," J9!(t9枏Lf)8͢.Vo{+E~?f&*eiU )2:mܐZܕY,и̔ M.JL)}&`r~R&>

已知1/x-1/y=4,求(2x+xy-2y)/(x-2xy-y)的值
已知1/x-1/y=4,求(2x+xy-2y)/(x-2xy-y)的值

已知1/x-1/y=4,求(2x+xy-2y)/(x-2xy-y)的值

1/x-1/y=4,所以y-x=4xy

1/x-1/y=4
∴y-x=4xy
(2x+xy-2y)/(x-2xy-y)
=[2(x-y)+xy]/[(x-y)-2xy]
=(-8xy+xy)/(-4xy-2xy)
=-7xy/(-6xy)
=7/6