若2x²+xy+3y²=-5,求(9x²+2xy+6)-(xy+7x²-3y²-5)的值
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若2x²+xy+3y²=-5,求(9x²+2xy+6)-(xy+7x²-3y²-5)的值
若2x²+xy+3y²=-5,求(9x²+2xy+6)-(xy+7x²-3y²-5)的值
若2x²+xy+3y²=-5,求(9x²+2xy+6)-(xy+7x²-3y²-5)的值
答案为6,因为(9x²+2xy+6)-(xy+7x²-3y²-5)算出为2x²+xy+3y²+11,2x²+xy+3y²又=-5.所以(9x²+2xy+6)-(xy+7x²-3y²-5)=2x²+xy+3y²+11=11-5=6