x,y满足√(2x-3)+y^3+√(3-2x)=-8则xy等于A.-3 B.3 C.-4/3

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x,y满足√(2x-3)+y^3+√(3-2x)=-8则xy等于A.-3 B.3 C.-4/3
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x,y满足√(2x-3)+y^3+√(3-2x)=-8则xy等于A.-3 B.3 C.-4/3
x,y满足√(2x-3)+y^3+√(3-2x)=-8则xy等于
A.-3 B.3 C.-4/3

x,y满足√(2x-3)+y^3+√(3-2x)=-8则xy等于A.-3 B.3 C.-4/3
答案选 A
计算方法:
2x-3 >= 0 => x >= 3/2
3-2x >= 0 => x =< 3/2
综上所得 x = 3/2
代入方程解得 y = -2
所以 xy = -3